Back

Rotate Array by K Number | LeetCode

Copy Below Code View As A Text File Show Text Only Show API Edit Code
                            

Q = https://leetcode.com/explore/interview/card/top-interview-questions-easy/92/array/646/ =========== Leet Code Solution ================= /** * @param {number[]} nums * @param {number} k * @return {void} Do not return anything, modify nums in-place instead. */ var rotate = function(nums, k) { if(nums.length <=0) return 0; k = k % nums.length; // Step 1 - Reverse whole Array nums = nums.reverse(); // Step 2 - Reverse Array from start to k-1 reverseArr(nums,0,k-1); // Step 3 - Rever from k to end reverseArr(nums,k,nums.length-1); }; function reverseArr(arr,start,end){ while(start < end){ let temp = arr[start]; arr[start] = arr[end]; arr[end] = temp; start++; end--; } } ==== Solution 1 ====== nums = [1,2,3,4,5,6,7], k = 3 function code(){ const nums= [1,2,3,4,5,6,7]; const k = 3; var finalArr=[]; if(nums.length <=0) return 0; var count=1; for (var i = nums.length - 1; i >= 0; i--) { if(count <= k){ finalArr.push(nums[i]); nums.splice(i); // remove element from Specific Index } count++; } var finalArr= finalArr.concat(nums); console.log(finalArr); } code();